What was your son's mathematical problem?
"write down an nth term formula for the original sequence
12 26 46 72 104 142"
a Freddered gold 1 point star to the first (non maths teacher) who can come up with the correct answer
At 13yo your child is probably only just being introduced to quadratics.
The first and second differences are precisely that:
The first difference being the difference between each consecutive number in the series.
The second difference being the differences between each of the first differences.
series: 12 26 46 72 104 142
1st diff: 14 20 26 32 38
2nd diff: 6 6 6 6
The second diff being constant implies function including x^2
your son is therefore familiar with series and y=ax+b I expect this is to then build on this to reach y=ax^2+bx+c
For instance if you write the series x^2
1 4 9 16 25 36, the first differences are 3, 5, 7, 9, 11 ... the second differences are 2, 2, 2, 2, 2
therefore A in the term Ax^2 is the second differential /2
then write out the series 3x^2 and subtract from the original series to leave 9 14 19 24 29 34. This new series is of the form 5x +b as the first difference is 5, this is 5x+4. Therefore the final function is 3n^2 + 5n + 4