He was trying to find a lowest common denominator in order to order fractions.
4/16 2/6 3/4 1/2 6/10 and 1/8 ...
Isn't the obvious brute force approach to just multiply all of the denominators by all of the other denominators?
Yes. Well, it is if you're of a computer science persuasion, anyway. I started doing that then realised it probably wasn't what the junior school maths lot would have in mind, and opted for the same sort of frustratingly non-algorithmic method that we were taught to use at A-level for integration: Staring at it for a bit, cancelling where appropriate, then pulling the answer out of thin air.
I can't help thinking that a Chinese Room approach to maths teaching would have made life a lot less complicated...
Start by simplifying the fractions 4/16 = 1/4, 2/6 = 1/3 and 6/10 = 3/5
Take all the denominators, 4, 3, 4, 2, 5, 8
set aside any that are factors of one of the others, in this case 4, and 2 to reduce the set to 3, 8, 5
Multiply out to get 120
now multiply each denominator and numerator by the required amount to get to the X/120
a)30/120, b)40/120, c)90/120, d)60/120, e)72/120 and f)15/120
reorder largest first: c) e) d) b) a) f)
translate back to original fractions:
3/4, 6/10, 1/2, 2/6, 4/16, 1/8
I admit to initially not simplifying the fractions which leads to working in X/240 and more faff.